Question

2x^+7x-4 factorise the following by middle terms​

Answer 1

$\underline{\LARGE{\orange{\sf{Answer:}}}}$

$\implies \red{\sf{2x^2 + 7x - 4 = 0}}$

$\implies \sf{2x^2 + 8x - x - 4 = 0}$

$\implies \sf{2x(x + 4) - 1(x + 4) = 0}$

$\implies \sf{(x + 4)(2x - 1) = 0}$

$\implies ∴ \sf{\orange{x = - 4} \:\green{and}\:\pink{x = \frac{1}{2}}}$

Answer 2

Answer:

(2x-1)(x+4)

Step-by-step explanation:

2x^2 + 7x -4

2x^2 + 8x-x -4

2x(x+4).-1(x+4)

2x-1)(x+4)