2x+7y =11
3x =y+5
solve by substitution method
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2x + 7y = 11
3x=y+5
2x+7y=11÷3
3x-1y=5÷2
6x+21y=33
6x-2y=10
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23y=23
y=1
sub 2x+7y=11 ,y=1
2x+7(1)=11
2x+7=11
2x=11-7
2x=4
x=4/2
x=2
hence x=2 and y=1
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