Find the area of the triangle formed by joining the
midpoints of the sides of the triangle wh
vertices are A(2, 3), B (4,4), C (2,6).
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Answer:[ 8/3 , 13/3 ]
I hope this is the right answer
I am not sure but, here u go
Step-by-step explanation:
let us take co-ordinates A(x1,y1); B(x2,y2); C(x3,y3)
according to question,
the mid-point of triangle ABC is
[x1+x2+x3/3 , y1+y2+y3/3]
⇒ [2+4+2/3 , 3+4+6/3]
= [8/3 , 13/3]
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