2x articles cost rs. ( 5x + 54 ) and ( x + 2 ) similar articles cost rs. ( 10x - 4 ) . Find x .
Chap : Quadratic Equations , Class 10 .Plz help !!
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Given that 2x articles cost 5x + 54.
Given that (x + 2) articles cost (10x - 4).
Now,
2x/x + 2 = 5x + 54/10x - 4.
On cross-multiplication, we get
2x(10x - 4) = (x + 2)(5x + 54)
20x^2 - 8x = 5x^2 + 54x 10x + 108
15x^2 - 72x - 108 = 0
5x^2 - 24x - 36 = 0
5x^2 - 30x + 6x - 36 = 0
5x(x - 6) + 6(x - 6) = 0
(5x + 6)(x - 6) = 0
x = -6/5 (or) x = 6.
Hope this helps!
Given that (x + 2) articles cost (10x - 4).
Now,
2x/x + 2 = 5x + 54/10x - 4.
On cross-multiplication, we get
2x(10x - 4) = (x + 2)(5x + 54)
20x^2 - 8x = 5x^2 + 54x 10x + 108
15x^2 - 72x - 108 = 0
5x^2 - 24x - 36 = 0
5x^2 - 30x + 6x - 36 = 0
5x(x - 6) + 6(x - 6) = 0
(5x + 6)(x - 6) = 0
x = -6/5 (or) x = 6.
Hope this helps!
steeve:
thx dude
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