2x-ky+ 3 = 0 ; 3x +2y -1 =0
Find k for which the eq. Have a unique solution
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Heya !!
2X - KY + 3 = 0 and 3X + 2Y - 1 = 0
This equation is of the form of :
A1X + B1Y + C1 = 0 and A2X + B2Y + C2 = 0
Where,
A1 = 2 , B1 = -K , C1 = 3 and A2 = 3 , B2 = 2 , C2 = -1
For a unique solution , we must have
A1/A2 # B1/B2 [ Where # stands for not equal]
2/3 # -K/2
-3K # 4
K # - 4/3
Hence,
K has all real values , other than -4/3.
2X - KY + 3 = 0 and 3X + 2Y - 1 = 0
This equation is of the form of :
A1X + B1Y + C1 = 0 and A2X + B2Y + C2 = 0
Where,
A1 = 2 , B1 = -K , C1 = 3 and A2 = 3 , B2 = 2 , C2 = -1
For a unique solution , we must have
A1/A2 # B1/B2 [ Where # stands for not equal]
2/3 # -K/2
-3K # 4
K # - 4/3
Hence,
K has all real values , other than -4/3.
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