Math, asked by aayushsingh881pavzp3, 1 year ago

2x-ky+ 3 = 0 ; 3x +2y -1 =0

Find k for which the eq. Have a unique solution

Answers

Answered by Panzer786
10
Heya !!

2X - KY + 3 = 0 and 3X + 2Y - 1 = 0

This equation is of the form of :

A1X + B1Y + C1 = 0 and A2X + B2Y + C2 = 0

Where,

A1 = 2 , B1 = -K , C1 = 3 and A2 = 3 , B2 = 2 , C2 = -1

For a unique solution , we must have

A1/A2 # B1/B2 [ Where # stands for not equal]

2/3 # -K/2

-3K # 4

K # - 4/3

Hence,

K has all real values , other than -4/3.
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