(2x) ^ln2 = (3y)^ln3
Solve for x
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Given,
(2x)^ln2= (3y)^ln3
taking log both sides we get
ln2.log(2x)= ln3.log(3y)
Now differentiate w.r.t. x we get
ln2.(1/2x).d/dx(2x)= ln3.(1/3y).d/dx(3y)
=> ln2/2x.(2)=ln3/3y.(3dy/dx)
=> ln2/x= ln3/y.dy/dx
=>dy/dx=(ln2/ln3).(y/x) Ans.
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