2x^n=9x^m .then find th value of m&n
Answers
Hey mate....
here's the answer....
3x²-2mx+2n = 0
3(2)²-2m(2)+2n = 0
3(4)-4m + 2n = 0
12-4m+2n = 0
-4m+2n = -12.......1)
fill x = -3
3x²-2mx+2n = 0
3(-3)²-2m(-3)+2n = 0
3(27)+6m +2n = 0
81+6m+2n = 0
6m + 2n = -81........2)
by equation (1) and (2)
-4m+2n = -12
6m +2n = -81
(-). (-). (+)
__________
-10m = 69
m = 69/-10
m = -69/10
then put value of m in any equation
-4m + 2n = -12
-4(-69/10)+2n = -12
276/10+12 +2n = 0
276+120/10+2n = 0
396/10 +2n = 0
2n = -396/10
n = -396/10×1/2
n = -396/20
n = -198/10
Hope this helps❤
Heya ____
First put x = 2
3x^2 -2mx + 2n =0
3(2^2) - 2m(2) +2n = 0
3(4) -4m + 2n = 0
12 -4m +2n = 0
-4m +2n = -12 ___________ 1
Now ____ x = - 3
3 ( -3^2) - 2m ( -3) + 2n = 0
3(27) +6m + 2n = 0
6m + 2n = -81 ___________ 2
By substracting both equation ...
We get ___
- 10m = 69
m = 69/-10
put m in any equation ______
-4m + 2n =-12
-4( -69/10) +2n = -12
396/10 +2n =>0
2n = -396/20
n = -198/10 _____ Ans
Thank you