Question

√2x square-3x-2√2=0 using quadratic formula​

Answer 1

Answer:

$a = \sqrt{2} \: \: b = - 3 \: \: c = - 2 \sqrt{2} \\ d = {b}^{2} - 4ac \\ d = {( - 3)}^{2} - 4( \sqrt{2} )( - 2 \sqrt{2} ) \\ d = 9 + 16 \\ d = 25$

$x = \frac{ - b + - \sqrt{d} }{2a} \\ x = \frac{ - ( - 3) + - \sqrt{25} }{2 \sqrt{2} } \\ x = \frac{3 + 5}{2 \sqrt{2} } and \: \: x = \frac{3 - 5}{2 \sqrt{2} } \\ x = \frac{8}{2 \sqrt{2} } \: and \: x = \frac{ - 3}{2 \sqrt{2} } \\ x = \frac{4}{ \sqrt{2} } \: and \: x = \frac{ - 6 \sqrt{2} }{8} \\ x = \frac{4 \sqrt{2} }{2} \: and \: x = \frac{ - 3 \sqrt{2} }{4} \\ x = 2 \sqrt{2} \: and \: x = \frac{ - 3 \sqrt{2} }{4}$

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