Question

2x square-3x-3=0 by formula method​

Answer 1

Answer:

a=2, b=-3 and c=-3

=-b±√b^2 - 4ac / 2a

=3±√9 - 4×2×-3 / 2×2

=3±√9 + 24 / 4

=3±√33 / 4

first root,

3+√33 /4

=(3)^2+(√33) ^2 / (4) ^2

=9+33/16

=42/16

=21/8

second root,

3-√33 / 4

=9- 33 / 16

=-24 / 16

= -3/2

therefore, the roots are 21/8 and -3/2.