Question

2x square -3x +7 evaluate the quadratic equation example alpha square and beta square

Answer 1

Step-by-step explanation:

let

$let \: \: \alpha \: \: be \: a \: and \beta \: as \: b$

a^2 +b^2 = (a+b)^2 - 2ab

=(sum of zeroes)^2 - 2*(product of zeroes)

= (-b/a)^2 - 2* (c/a)

here a=2, b=-3 and c=7

substituting the values

=> (3/2)^2 - 2*(7/2) = 9/4-7 = 2.25 - 7= -4.75

answer. -4.75

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