Question

2x square + y square + 8z square - 2 root 2xy + 4 root 2yz - 8xz

Answer 1

2x^2 + y^2 + 8z^2 - 2√2xy+ 4√2yz-8xz
=(-√2x)^2+(y)^2+(2√2z)^2+2(-√2x)(y)+2(y)(2√2z)+2(-√2x)(2√2z)
=(-√2x+y+2√2z)^2
=(-√2x+y+2√2z)(-√2x+y+2√2z)