Math, asked by vinaybhardwaj267, 9 months ago

2x
2x { }^{2}   - 3x + 1

Answers

Answered by Anonymous
1

Answer:

2 {x}^{2}  - 3x + 1 \\ 2 {x}^{2}  - 2x - x + 1 \\ 2x(x - 1) - 1(x - 1) \\ (2x - 1)(x - 1) \\ if \\ 2x - 1 = 0 \\ x =  \frac{1}{2}  \\ if \\ x - 1 = 0 \\ x = 1

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Answered by anshi60
27

\implies2 {x}^{2}  - 3x + 1 = 0 \\  \\  \implies2 {x}^{2}  - 2x - x + 1 = 0 \\  \\ \implies \: 2x(x - 1) + 1(x - 1) = 0 \\  \\ \implies(2x + 1)(x  - 1) = 0 \\  \\ \implies \: x =  \frac{ - 1}{2} \:  and \: x = 1

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