Math, asked by rakhisingh80h, 9 months ago

5. If the HCF of 65 and 117 is expressible in the form 65 m – 117, then the value of m is​

Answers

Answered by pranavjella9999
2

Answer:

By Euclid's divison algorithm, <br>

[dividend=

+remainder] <br>

<br>

<br>

<br>

HCF(65,117)=13

Rightarrow 65m=130

Answered by Anonymous
25

 \mathtt{\huge{ \fbox{Solution :)}}}

Given ,

The HCF of 65 and 117 is expressible in the form 65m – 117

By Euclid's divison algorithm ,

117 = 65 × 1 + 52

65 = 52 × 1 + 13

52 = 13 × 4 + 0

Hence , the HCF of 65 and 117 can be expressible in the form of 65m - 117

Since , HCF of 65 and 117 can be 65m – 117

Thus ,

13 = 65m – 117

65m = 130

m = 130/65

m = 2

Hence , the value of m is 2

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