Question

2x- x2 rate of reaction becomes 27 times when conc of x increases 3 times.What is the order of the reaction

Answer 1

Solution :

Let the rate law for the reaction be r=k[A]n

According to the question,

27r=k[3A]n

Dividing equation (ii) by equation (i) we get

27rr=k[3A]nk[A]n

or 33=3n

order of reaction n=3

Answer 2

The order of the reaction is 3

Explanation:

$2X\rightarrow X_2$

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$rate=k[X]^n$

k= rate constant

x = order with respect to X

$rate=k[X]^n$   (1)

Rate of reaction becomes 27 times when concentration of X increases 3 times.

$rate'=k[3X]^n$

$27\times rate=k[3X]^n$     (2)

Dividing (2) by (1)

$27=3^n$

$3^3=3^n$

$n=3$

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