2x-y=1 x+2y=13 by using substitution method
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1
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Here is your answer......☺
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➡ By substitution method :
2x - y = 1 -----------(1)
x + 2y = 13 --------------(2)
From (1) we have,
2x - 1 = y -----------(3)
Now, putting value of y in equation (2) we get:
=> x + 2y = 13
=> x + 2 ( 2x - 1) = 13
=> x + 4x - 2 = 13
=> 5x = 13 +2
=> 5x = 15
=> x = 15/5
=> x = 3
From (3) we have,
2x - 1 = y
=> 2 × 3 - 1 = y
=> 6 - 1 = y
=> y = 5
==================================
Thanks....☺
Here is your answer......☺
=================================
➡ By substitution method :
2x - y = 1 -----------(1)
x + 2y = 13 --------------(2)
From (1) we have,
2x - 1 = y -----------(3)
Now, putting value of y in equation (2) we get:
=> x + 2y = 13
=> x + 2 ( 2x - 1) = 13
=> x + 4x - 2 = 13
=> 5x = 13 +2
=> 5x = 15
=> x = 15/5
=> x = 3
From (3) we have,
2x - 1 = y
=> 2 × 3 - 1 = y
=> 6 - 1 = y
=> y = 5
==================================
Thanks....☺
Answered by
1
in substitution method
2x -y =1
y=2x-1......(3)
putting y=2x+1 in (2)
=3
[tex]y = 2x-1
[tex]y = 2×3-1
[tex]y = 5
2x -y =1
y=2x-1......(3)
putting y=2x+1 in (2)
=3
[tex]y = 2x-1
[tex]y = 2×3-1
[tex]y = 5
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