(2x+y) ² expand it using standard formula
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\begin{gathered} {(2x - y + z)}^{2} \\ \\ using \: the \: identity \\ {(a - b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} - 2ab - 2bc + 2ca \\ \\ = {(2x)}^{2} + {(y)}^{2} + {(z)}^{2} - 2 \times 2x \times y - 2 \times y \times z + 2 \times z \times 2x \\ \\ = 4 {x}^{2} + {y}^{2} + {z}^{2} - 4xy - 2yz + 4xz\end{gathered}(2x−y+z)2usingtheidentity(a−b+c)2=a2+b2+c2−2ab−2bc+2ca=(2x)2+(y)2+(z)2−2×2x×y−2×y×z+2×z×2x=4x2+y2+z2−4xy−2yz+4xz
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