Math, asked by Sundamikel7422, 9 months ago

2x+y–3=0,2x–3y–7=0 solve using substitution method

Answers

Answered by nuhmanaljafri
8

Step-by-step explanation:

If 2x + y - 3 = 0, and 2x - 3y - 7 = 0,

2x + y - 3 = 2x - 3y - 7

[2x cancels out on both sides] = y - 3 = (-3y) - 7

y = - 3y - 4 OR 4 = (-3y) - y = (-4y)

Therefore, y = (- 4) / 4 = (-1)

By substituting y in one of the equations,

2x + (-1) - 3 = 0 OR 2x = 0 + 4 = 4

Therefore, x = 2

Substituting all the values to clarify,

2(2) + (-1) - 3 = 4 - 1 - 3 = 0

2(2) - 3(-1) - 7 = 4 + 3 - 7 = 0

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