Question

2x-y-3=0and 4x+y-3=0by Cross multiplication

Answer 1

from these you will get
x=1 and y=-1

Answer 2

Answer:

Solution :-

The given equations are;

2x - y - 3 = 0

4x + y - 3 = 0

By Cross multiplication rule, we get

$\dfrac{x}{1(- 3) - 1(- 3)} = \dfrac{y}{4(- 3) - 2(- 3)} = \dfrac{1}{2(1) - 4(1)}$

$\dfrac{x}{- 3 + 3} = \dfrac{y}{- 12 + 6} = \dfrac{1}{2 - 4}$

$\dfrac{x}{0} = \dfrac{y}{- 6} = \dfrac{1}{- 2}$

$\Rightarrow$ $\dfrac{x}{0} = \dfrac{1}{- 2}\: and\: \dfrac{y}{- 6} = \dfrac{1}{- 2}$

$\Rightarrow$ $x = \dfrac{0}{- 2}\: and\: y\: = \dfrac{- 6}{- 2}$

$\Rightarrow$ $x\: = 0\: \:and\: y\: = 3\:$

$\therefore$ $The\: value\: of\: x\: = 0\:, y\: = 3\: is\: the\: solution\: of\: the\: system\: of\: the\:given\: equations.\:$