Math, asked by Anisha5119, 11 months ago

(2x-y+3) (2x-y-3) expand ​

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Answers

Answered by BrainlyPopularman
4

Answer:

GIVES THAT -

(2x - y + 3)(2x - y - 3)

EXPAND :-

PUT

2x - y = t

So,

(t + 3)(t - 3) =  {t}^{2}  - 9

SO THAT -

 =  {(2x - y)}^{2}  - 9 \\  \\  = 4 {x}^{2}  +  {y}^{2}  - 4xy - 9

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Answered by abavasri22
0

Answer:

3)(2x−y+3)(2x−y−3)

EXPAND :-

PUT

2x - y = t2x−y=t

So,

(t + 3)(t - 3) = {t}^{2} - 9(t+3)(t−3)=t

2

−9

SO THAT -

\begin{gathered} = {(2x - y)}^{2} - 9 \\ \\ = 4 {x}^{2} + {y}^{2} - 4xy - 9\end{gathered}

=(2x−y)

2

−9

=4x

2

+y

2

−4xy−9

Step-by-step explanation:

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