(2x-y+3) (2x-y-3) expand
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Answered by
4
Answer:
GIVES THAT -
EXPAND :-
PUT
So,
SO THAT -
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Answered by
0
Answer:
3)(2x−y+3)(2x−y−3)
EXPAND :-
PUT
2x - y = t2x−y=t
So,
(t + 3)(t - 3) = {t}^{2} - 9(t+3)(t−3)=t
2
−9
SO THAT -
\begin{gathered} = {(2x - y)}^{2} - 9 \\ \\ = 4 {x}^{2} + {y}^{2} - 4xy - 9\end{gathered}
=(2x−y)
2
−9
=4x
2
+y
2
−4xy−9
Step-by-step explanation:
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