Question

2x+y-35=0,3x+4y-65=0 solve by substution method​

Answer 1

$\huge \color{green} \bigstar{answer}$

$2x + y = 35 \: \: \: \: (i)$

$3x + 4y = 65 \: \: \: (ii)$

$using \: substitution \: method$

$from \: equation(i) \: we \: get$

$2x + y = 35$

$x = \frac{35 - y}{2} \: \: \: \: \: \: (iii)$

$putting \: x = \frac{35 - y}{2} \: in \: {eq}^{n} \: (ii)$

$3x + 4y = 65$

$3( \frac{35 - y}{2} ) + 4y = 65$

$105 - 3y + 8y = 130$

$5y = 130 - 105$

$y = \frac{25}{5}$

$y = 5$

$putting \: y = 5 \: in \: {eq}^{n} (iii)$

$x = \frac{35 - y}{2}$

$x = \frac{35 - 5}{2}$

$x = \frac{30}{2}$

$x = 15$

$so \: x = 15 \: and \: y = 5$