-2x+y+4z whole square
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Answered by
1
we know,(a+b)^2=a^2+b^2+2ab
In this qn,take (-2x+y)=a and 4z=b.
Try and let me know.
In this qn,take (-2x+y)=a and 4z=b.
Try and let me know.
Answered by
0
(-2x)square+(y)square+(4z)square+2•-2x•y+2•y•4z+2•-2x•4z =4xspuare +ysquare+16zsquare -4xy+8yz-16xz
advik2488:
wrong
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