2x-y=5 ; 3x+2y=11 Solve the simultaneous equation.
Answers
Answered by
13
Hello!!
Here is your answer!
_____________________
2x - y = 5 ( 1 )
3x + 2y = 11 ( 2)
From ( 1 )
y = 2x - 5 ( 3 )
Substituting the value in ( 2 )
3x + 2 ( 2x - 5 ) = 11
3x + 4x - 10 = 11
7x = 21
x = 3
Hence the value of y ( Substitute in ( 3 ) )
y = 6 - 5 = 1
Hope it helps
Here is your answer!
_____________________
2x - y = 5 ( 1 )
3x + 2y = 11 ( 2)
From ( 1 )
y = 2x - 5 ( 3 )
Substituting the value in ( 2 )
3x + 2 ( 2x - 5 ) = 11
3x + 4x - 10 = 11
7x = 21
x = 3
Hence the value of y ( Substitute in ( 3 ) )
y = 6 - 5 = 1
Hope it helps
Answered by
44
Solution :
Given simultaneous equations
are ,
2x - y = 5
=> 2x - 5 = y
y = 2x - 5 -----( 1 )
3x + 2y = 11 ----( 2 )
Substitute y = 2x - 5 in equation
( 2 ) , we get
3x + 2(2x- 5 ) = 11
=> 3x + 4x - 10 = 11
=> 7x = 11 + 10
=> 7x = 21
=> x = 21/7
x = 3
Substitute x = 3 in equation ( 1 ),
We get ,
y = 2×3 - 5
=> y = 6 - 5 = 1
Therefore ,
x = 3 , y = 1
•••••
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