Question

2x+y=6 and 3y=8+4x solve by substitution method​

Answer 1

2x+y=6

3y=8+4x

y=6-2x

substitute Y =6 - 2x in equation 2

3y=8+4x

3(6-2x)=8+4x

18-6x=8+4x

18-8=4x+6x

10=10x

x=10/10

x=1

Put x is equal to 1 in equation 1.

2x+y=6

2(1)+y=6

y=6-2

y=4

Answer 2

$\Large{\underline{\underline{\mathfrak{\bf{Question}}}}}$

2x+y=6 and 3y=8+4x solve by substitution method ?

$\Large{\underline{\underline{\mathfrak{\bf{Solution}}}}}$

$\Large{\underline{\mathfrak{\bf{\pink{Given}}}}}$

• 2x + y = 6 ........(1)
• 4x - 3y = 8 .......(2)

$\Large{\underline{\underline{\mathfrak{\bf{Explanation}}}}}$

$\large{\underline{\mathfrak{\bf{By\:Substitution\:Method}}}}$

By equation(1) ,

• y = 6 - 2x.....(3), keep in (2)

$\mapsto\sf{\:4x-3(6-2x)\:=\:8} \\ \\ \mapsto\sf{\:4x\:=\:18-6x+8} \\ \\ \mapsto\sf{\:4x+6x\:=\:26} \\ \\ \mapsto\sf{\:10x\:=\:26} \\ \\ \mapsto\sf{\:x\:=\:\dfrac{26}{10}}$

keep value of x in equ(3),

$\mapsto\sf{\:y\:=\:6-\:2.\dfrac{26}{10}} \\ \\ \mapsto\sf{\:y\:=\:\dfrac{-52}{10}+6} \\ \\ \mapsto\sf{\:y\:=\:\dfrac{-52+60}{10}} \\ \\ \mapsto\sf{\:y\:=\:\dfrac{8}{10}}$

Thus:-

• Value of x = 26/10
• Value of y = 8/10

$\Large{\underline{\mathfrak{\bf{\pink{Answer\:Verification}}}}}$

keep value of x and y in equ(1)

$\mapsto\sf{\:2.\dfrac{26}{10}+\dfrac{8}{10}\:=\:6} \\ \\ \mapsto\sf{\:\dfrac{52}{10}+\dfrac{8}{10}\:=\:6} \\ \\ \mapsto\sf{\:\dfrac{52+8}{10}\:=\:6} \\ \\ \mapsto\sf{\:\dfrac{\cancel{60}}{\cancel{10}}\:=\:6} \\ \\ \mapsto\sf{\:6\:=\:6} \\ \\ \mathfrak{\bf{\:\:\:\:\:\:L.H.S.\:=\:R.H.S.}}$

That's proved,

Hence, we can say that our solution is absolutely right