Math, asked by jainrishabh2005, 9 months ago

If the HCF and LCM of two positive integers a and b are x and y ,then x²y²/a²b²=

Answers

Answered by Anonymous
58

\large{\underline{\underline{\mathfrak{Answer :}}}}

  • Value of x²y²/a²b² = xy/ab

Or

  • Value x²y²/a²b² = 1

\rule{200}{0.5}

\underline{\underline{\mathfrak{Step-By-Step-Explanation :}}}

Given :

  • 1st Integer = a
  • 2nd Integer = b
  • H.C.F = x
  • L.X.M = y

\rule{200}{2}

To Find :

  • Value of x²*y²/a²b²

\rule{200}{2}

Solution :

Use formula :

\large{\boxed{\sf{L.C.M \: \times \: H.C.F \: = \: Product \: of \: numbers}}} \\ \\ \implies {\sf{xy \: = \: ab}} \\ \\ \footnotesize{\underline{\sf{\dag \: \: \: \: \: \: \: Multiply \: abxy \: both \: sides \: \: \: \: \: \: \:}}} \\ \\ \implies {\sf{xy \: \times \: abxy \: = \: ab \: \times \: abxy}} \\ \\ \implies {\sf{x^2y^2 \: \times \: ab \: = \: a^2 b^2 \: \times \: xy}} \\ \\ \implies {\sf{\dfrac{x^2y^2}{a^2 b^2} \: = \: \dfrac{xy}{ab}}} \\ \\ \Large{\boxed{\sf{\dfrac{x^2 y^2}{a^2 b^2} \: = \: \dfrac{xy}{ab}}}}

\rule{200}{2}

\implies {\sf{xy \: = \: ab}} \\ \\ \footnotesize{\underline{\sf{\dag \: \: \: \: \: \: \: Square \: Both \: sides \: \: \: \: \: \: \:}}} \\ \\ \implies {\sf{(xy)^2 \: = \: (ab)^2}} \\ \\ \implies {\sf{x^2 y^2 \: = \: a^2 b^2}} \\ \\ \implies {\sf{\dfrac{x^2 y^2}{a^2 b^2} \: = \: 1}} \\ \\ \Large{\boxed{\sf{\dfrac{x^2 y^2}{a^2 b^2} \: = \: 1}}} \\ \\ \underline{\sf{\therefore \: Value \: \: of \: \: \dfrac{x^2y^2}{a^2b^2} \: \: is \: \:  \large{\sf{\dfrac{xy}{ab} \: \:  or \: \: 1}} \: }}

Answered by RvChaudharY50
109

Given :-

  • HCF and LCM of two positive integers a and b are x and y .

To Find :-

  • (x²y²)/(a²b²) = ?

Concept Used :-

  • The product of the H.C.F. and the L.C.M. of two numbers is equal to the product of the given numbers.

Solution :-

From Given Data we Have :-

First Number = a

→ Second Number = b

→ HCF of a & b = x

→ LCM of a & b = y .

So, From Above Told concept we can say that ,

First Number * Second Number = HCF * LCM .

Or,

( a × b) = (x × y)

Squaring Both sides we get,

( a × b)² = (x × y)²

→ a²b² = x²y² -------------- Equation (1)

Now, Putting value of Equation (1) we get,

(x²y²)/(a²b²)

→ (x²y²) / (x²y²)

→ 1 (Ans).

Or,

(a²b²) / (a²b²)

→ 1 (Ans).

_____________________________

★★Extra Brainly Knowledge★★

✯✯ Some Properties of HCF & LCM ✯✯

HCF(Highest Common Factor) :- The largest or greatest factor common to any two or more given natural numbers is termed as HCF of given numbers. Also known as GCD (Greatest Common Divisor).

LCM(Least Common Multiple) :- The least or smallest common multiple of any two or more given natural numbers are termed as LCM.

☛ The H.C.F. of given numbers is not greater than any of the numbers.

☛ The L.C.M. of given numbers is not less than any of the given numbers.

☛ The H.C.F. of two co-prime numbers is 1.

☛ The L.C.M. of two or more co-prime numbers is equal to their product.

☛ If a number, say x, is a factor of another number, say y, then the H.C.F. of x and y is x and their L.C.M. is y.

☛ The product of the H.C.F. and the L.C.M. of two numbers is equal to the product of the given numbers. That is, if a and b are two numbers, then a x b = H.C.F. x L.C.M.

☛ LCM of fractions = ( LCM of Numerators ) / ( HCF of Denominators ) .

☛ HCF of fractions = ( HCF of Numerators ) / ( LCM of Denominators ) .

______________________________

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