Math, asked by pk6972345, 10 months ago

-2x+y=7and+4x-3y=9 substitute elimination​

Answers

Answered by Anonymous
2

Answer:

Step-by-step explanation:

-2x+y=7

2x-y+7=0........equ(1)

4x-3y=9

4x-3y-9=0......equ(2)

3(2x-y+7)=0

6x-3y+21=0....equ(3)

1(4x-3y-9)=0

4x-3y-9=0...equ(4)

equ(3)-equ(4)

6x-3y+21=0

4x-3y-9=0

___________

2x+30=0

2x=-30

x=-30/2=-15

4x-3y=9

4×-15-3y=9

-60-3y=9

-3y=60+9

-3y=69

y=69/-3=-23

Answered by Anonymous
2

substitution method:-

-2x+y=7 (eq1)

4x-3y=9 (eq2)

let we take 1st equation

y=7+2x

∴ Substituting value of y in equation 2

4x -3(7+2x)=9

4x-21-6x=9

4x-6x=9+21

-2x=30

x=-30/2

x=-15

∴ substituting value of x in 1st equation

-2(-15)+y=7

30+y=7

y=7-30

y=-23

elimination method:-

                                     -2x+y=7 (eq1)

                                             4x-3y=9 (eq2)

let we multiply -2 with equation 1 and subtract equation1 from equation 2

         4x-2y=-14

           4x-3y=9

y=-23

∴ substitute value of y in equation1

4x-2(-23)=-14

4x=-14-46

x=-60/4

x=-15

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