verify x³+y³=(x+y)(x²-xy+y²)
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We have to prove that x³ - y³ = (x-y)(x² + xy + y²)
So, Let's take R. H. S and prove it equal to L.H. S.
R. H. S
= (x-y)(x² + xy + y²)
= x ( x² + xy + y² ) - y ( x² + xy + y²)
= x³ + x²y + xy² -yx² -xy² - y³
= x^3 + \cancel{ x^2 y } + \cancel{ x y^2 } - \cancel{ x^2 y } - \cancel{ x y^2 } -y^3
= x³ - y³
= L. H. S.
Hence : LHS = RHS
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Explanation:
RHS = (x+y) (x² + xy + y²)
= x³ + x²y + xy² + x²y + xy² + y³
= x³ + y³
this is equal to LHS
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