Question

(2x - y + z.)^2 expand this​

Answer 1

Answer:

$\sf{}4x^{2} + y^{2} + z^{2} - 4xy - 2yz + 4zx$

Explanation:

Use identity :-

$\sf{}( a + b + c )^{2}= a^{2}+b^{2}+c^{2}+2ab+2bc+2ca$

Where

a=2x

b=-y

c=z

Therefore,

$\rightarrow\sf{} (2x)^{2}+(-y)^{2}+z^{2}+2(2x)(-y)+2(-y)z+2z(2x)\\ \\\rightarrow \sf{}4x^{2} + y^{2} + z^{2} - 4xy - 2yz + 4zx\\ \\ \because \sf{} Expansion\ of\ (2x - y + z)^2\ is\ 4x^{2} + y^{2} + z^{2} - 4xy - 2yz + 4zx$