Question

2x-y+z=4,x+y+z=1,x-3y-2z=2

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Answer 1

$= > 2x - y + z = 4 \\ = > 2x = y - z + 4 \\ = > x = \frac{y - z + 4}{2}$

$= > x + y + z = 1 \\ = > y + z = 1 - x$

$= > x - 3y - 2z = 2 \\ = > \frac{y - z + 4}{2} - 3y \: - 2z = 2 \\ = > \frac{y - z + 4 - 6y - 4z}{2} = 2 \\ = > - 5y - 5z = 8 \\ = > - 5(y + z) = 8 \\ = > y + z = - \frac{8}{5}$

Therefore

$= > - \frac{8}{5} = 1 - x \\ = > - 8 = 5 - 5x \\ = > 5x = 13 \\ = > x = \frac{13}{5}$

Similarly,

$y = 3 \\ and \\ z = - \frac{23}{5}$