Question

2x²-1/2x=0...solve by factorization method

Answer 1

2x2-1/2x=0

2x-1=0

2x=1

x=1/2

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Answer 2

Given:

$\mathbf{2x^{2}-\dfrac{1}{2}x=0}$

To Find:

Find roots of given equation by factorization method.

Solution:

$\mathbf{2x^{2}-\dfrac{1}{2}x=0}$

This can also be written as:

$\mathbf{2x^{2}-\dfrac{x}{2}=0}$

Taking x common from first and second term:

$\mathbf{x\left ( 2x-\dfrac{1}{2} \right )=0}$

Here product of two factor is zero, only when:

$\mathbf{ 2x-\dfrac{1}{2}=0}$                     OR  x = 0

$\mathbf{ 2x=\dfrac{1}{2}}$

$\mathbf{ x=\dfrac{1}{4}=0.25}$

So roots of equation is 0.25 and 0.