Question

2x²-2x+½=0 solve the quadratic e

Answer 1

Answer:

x = 1/2

Step-by-step explanation:

Factorising the given quadratic equation, we get :

$= > 2 {x}^{2} - 2x + \frac{1}{2} = 0 \\ \\ = > 4 {x}^{2} - 4x + 1 = 0 \\ \\ = > 4 {x}^{2} - 2x - 2x + 1 = 0 \\ \\ = > 2x(2x - 1) - 1(2x - 1) = 0 \\ \\ = > (2x - 1)(2x - 1) = 0 \\ \\ = > x = \frac{1}{2} \:or \: \frac{1}{2}\\ \\ = > x = \frac{1}{2} \: \: \: ans$

Thanks !!

Answer 2

Given ,

The polynomial is 2x² - 2x + ½

By middle term splitting method ,

$\sf \hookrightarrow 2 {(x)}^{2} - 2x + \frac{1}{2} = 0 \\ \\ \sf \hookrightarrow 4 {(x)}^{2} - 4x + 1 = 0 \\ \\ \sf \hookrightarrow 4 {(x)}^{2} - 2x - 2x + 1 = 0 \\ \\ \sf \hookrightarrow 2x(2x - 1) - 1(2x - 1) = 0 \\ \\ \sf \hookrightarrow (2x - 1)(2x - 1) = 0 \\ \\ \sf \hookrightarrow x = \frac{1}{2} \: \: or \: \: x = \frac{1}{2}$

$\therefore \underline{\sf \bold{The \: value \: of \: x \: is \: \frac{1}{2} }}$