Question

(2x²-3x+4) ÷ (x-1). Without doing actual division find the remainder by remainder theorem​

Answer 1

Answer:

$(2x {}^{2} - 3x + 4) \div ( \times - 1)$

$(2 x \times 2x)(3x + 4) \div (x - 1)$

$(4x - 3x - x) \div (4 - 1)$

$(0x) \div (3)$

$x = 3$

$is \: your \: right \: answer$

$100\%sure$

Answer 2

Answer:

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Step-by-step explanation:

(2x

2

−3x+4)÷(×−1)

(2 x \times 2x)(3x + 4) \div (x - 1)(2x×2x)(3x+4)÷(x−1)

(4x - 3x - x) \div (4 - 1)(4x−3x−x)÷(4−1)

(0x) \div (3)(0x)÷(3)

x = 3x=3

is \: your \: right \: answerisyourrightanswer

100\%sure100%sure