Question

√2x²+ 4x + 2root2 = 0​

Answer 1

Answer:D

√2x²+4x+2√2=0

a=√2, b= 4, c = 2√2

D = b²- 4ac.

D= (4)²-4(√2)(2√2)

D=16-16

D=0

√D= 0

Therefore D is 0, D has equal and disticint factors.

Factors = - b+ √D/2a, -b-√D/2a

-4+0/2√2, -4+0/2√2

-2/√2, -2/√2.

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Therefore, these are the two factors.

If you find my answer correct please mark me as the brainliest.......

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:D

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Thank you........