Question

2x²-5x+3=0 zolve by completing square method anyone ?​

Answer 1

Answer:

therefore x = 1;3/2

Step-by-step explanation:

$2x^2-5x+3=0$

thus product of roots =2x3

and sum of roots = -5

thus:

$2x^2-2x-3x+3=0$

$2x(x-1)-3(x-1)=0$

$(x-1)(2x-3)=0$

as in this anyone would be equal to 0 ;

X -1 or 2 X - 3 equal to 0

Answer 2

Answer:

x=3/2,1

Step-by-step explanation:

$2 {x}^{2} - 5x + 3 = 0 \\ \div \: the \:coefficient \: of \: {x}^{2} in \: the \: whole \: equation \\ {x}^{2} - \frac{5}{2} x + \frac{3}{2} = 0 \\ \div \: the \: coefficient \: of \: x \: by \: 2 \: and \: square \: it \: \\ ( { \frac{5}{4} )}^{2} = \frac{25}{16} \\ add \: and \: subtract \: in \: the \: equation \\ {x}^{2} - \frac{5}{2} x + \frac{3}{2} - \frac{25}{16} + \frac{25}{16} = 0 \\ ( {x}^{2} - \frac{5}{2} x + \frac{25}{16} ) = \frac{25}{16} - \frac{3}{2} \\ {(x - \frac{5}{4}) }^{2} = \frac{25 - 24}{16} \\ ( {x - \frac{5}{4} )}^{2} = \frac{1}{16} \\ squarring \: on \: both \: sides \: \\ x - \frac{5}{4} = plus \: or \: minus \: \frac{1}{4} \\ x = \frac{ 5 - 1}{4} = \frac{4}{4} = 1 \\ x = \frac{1 + 5}{4} = \frac{6}{4} = \frac{3}{2}$