Question

√2x²-6x+2√2 find its sum of zeros and its products

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hello Friend}}}$

Here is your answer
$a = \sqrt{2} \\ b = - 6 \\ c = 2 \sqrt{2}$
Sum of zeros = -b/a
$= - ( \frac{ - 6}{ \sqrt{2} } ) \\ = \frac{6}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ = 3 \sqrt{2}$
Product of zeros = c/a
$= \frac{2 \sqrt{2} }{ \sqrt{2} } \\ = 2$
Hope it helps you

Answer 2

Dear Student!!!

Question:-

√2x²-6x+2√2 find its sum of zeros and its products?

Method of Solution;-

Given;-

Equation : √2x²-6x+2√2

Now,



$\mathsf Sum \: of \: Zeroes = \frac{ - b}{a} \: \implies \: \frac{ - (coefficient \: of \: x}{coefficient \: of \: {x}^{2} } \\ \\ \\ \mathsf Sum \: of \: Zeroes = \frac{6}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{6 \sqrt{2} }{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3 \sqrt{2}$

$\mathsf product \: of \: Zeroes = \frac{ c}{a} \: \implies \: \frac{ (constant \: \: term}{coefficient \: of \: {x}^{2} } \\ \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \implies \: \frac{2 \sqrt{2} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ \\ \: \: \: \: \: \: \: \: \implies \: \frac{4}{2} \\ \\ \: \: \: \: \: \: \: \: \: \implies \: 2$

Hence, Sum of Zeroes = 3√2 and Product of Zeroes = 2