Question

2x²-7x+3=0, factorization method

Answer 1

Step-by-step explanation:

$2 {x}^{2} - 7x + 3 \\ \\ 2 {x}^{2} - 6x - x + 3 \\ 2x(x - 3) - 1(x - 3) \\ (2x - 1)(x - 3)$

Answer 2

Answer:

x=3,-1/2

Step-by-step explanation:

2x^2-7x+3=0

2x^2-x-6x+3=0

x(2x-1)-3(2x-1)=0

(2x+1)(x-3)=0

2x+1=0

2x=-1

x=-1/2

x-3=0

x=3

hope this will help you...