Question

2x2-7x+3=o by completing method find the roots of quadrant equations

Answer 1

$2 {x}^{2} + 7x + 3 = 0 \\ {x}^{2} + \frac{7x}{2} + \frac{3}{2} = 0 \\ {x}^{2} + \frac{7x}{2} = - \frac{3}{2} \\ {x}^{2} + \frac{7x}{2} + {( \frac{7}{4} })^{2} = - \frac{3}{2} + {( \frac{7}{4} })^{2} \\ ( {x + \frac{7}{4} })^{2} = - \frac{3}{2} + \frac{49}{16} \\ ( {x + \frac{7}{4} })^{2} = \frac{ - 24 + 49}{16} \\ ( {x + \frac{7}{4} })^{2} = \frac{25}{16} \\ x + \frac{7}{4} = \sqrt{ \frac{25}{16} } \\ x + \frac{7}{4} = \frac{5}{4} \\ x = \frac{5}{4} - \frac{7}{4} \\ x = \frac{5 - 7}{4} \\ x = \frac{ - 2}{2} \\ x = - 1$
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