Question

2x²+8xy+3y²=0 then show that dy/dx=y/x​

Answer 1

Answer:

4x+8dy/dx+6y.2dy/dx=0

4x+6y=dy/dx(-8/2)

Step-by-step explanation:

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Answer 2

Answer:

dy/dx = -(2x + 4y)/(4x + 3y)

Step-by-step explanation:

2x²+8xy+3y²=0

diff w.r.t. x

4x + 8(x.dy/dx + y.1) + 6y.dy/dx = 0

4x + 8xdy/dx + 8y + 6y.dy/dx = 0

2x + 4xdy/dx + 4y + 3ydy/dx = 0

4xdy/dx + 3ydy/dx = -(2x + 4y)

(4x + 3y)dy/dx = -(2x + 4y)

dy/dx = -(2x + 4y)/(4x + 3y)