Question

2x²-x+1/8=0 find the roots of quadratic equations by factorization
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Answer 1

Answer:

Hope this help u.......

Answer 2

Answer:$2x^{2} -x+1/8=0$

⇒ $16x^{2} -8x+1=0$

⇒$16x^{2} -4x-4x+1=0$

⇒$4x(4x-1)-(4x-1)$

⇒$(4x-1)(4x-1)=0$

⇒$(4x-1)=0 or (4x-1)$=0

⇒$x=1/4$