Math, asked by alishah18, 8 months ago

2x2-x-15=0 solve by completing square​

Answers

Answered by babyrai081gmailcom
1

Step-by-step explanation:

2x2-6x+5x-15=0

2x(x-3)+5(x-3)=0

(2x+5)(x-3)=0

x=3;-5/2

Answered by Anonymous
2

2x² - x - 15 = 0

= 2x² - 6x + 5x - 15 = 0

=> 2x(x-3)+5(x-3) = 0

=> (x-3)(2x+3) = 0

Either

x - 3 = 0

=> x = 3

Or

2x + 3 = 0

=> 2x = -3

=> x = -3/2

Hope it helps...

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