2x² +x - 3 = 0 by quadratic formula
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Answered by
8
given :-
2x² + x - 3
standard form of quadratic equation = ax² + bx + x
here a = 2, b = 1 and c = -3
D = (b)² - 4ac
= (1)² - 4(2)(-3)
= 1 - 4(-6)
= 1 + 24
= 25
since D is positive, it has 2 real and distinct roots.
now, x = (-b ± √D)/2a
➡ x = (-1 ± √25)/(2 × 2)
➡ x = (-1 ± 5)/4
➡ x = (-1 + 5)/4, x = (-1 - 5)/4
➡ x = 4/4 = 1, x = -6/4 = -3/2
hence, the roots of the quadratic equation are 1 and -3/2
Answered by
3
Answer:
X=1 or X=-3/2
Step-by-step explanation:
a=2,b=1,c=-3
by quadratic formula
x=-b±√(b²-4ac)/2a
x=-1±√(1)²-4(2)(-3)/2(2)
x=-1±√(1+24)/4
x=-1±√25/4
x=-1±5/4
x=-1+5/4 or -1-5/4
x=4/4 or -6/4
x=1 or x=-3/2
THANK YOU
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