Question

2x² - x-3 Factorise
Please tell it
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Answer 1

Answer:

2x² - x-3=2x²-3x² +x² -3

2x(x-3)+2(x-3)

(2x+2)(x-3).

Answer 2

Answer:

$\Rightarrow \Huge\boxed{\mathsf{(X+1)(2x-3)}}$

Step-by-step explanation:

TO FIND:

Find the factors of 2x²-x-3.

SOLUTIONS:

First, use distributive property.

DISTRIBUTIVE PROPERTY:

$\Rightarrow \displaystyle \mathsf{A(B+C)=AB+AC}\\\\\Rightarrow \displaystyle \mathsf{A(B-C)=AB-AC}$

Try to break the expression into their groups.

$\displaystyle \mathsf{(2x^2+2x)+(-3x-3)}$

Factor it out by the 2x from 2x²+2x.

EXPONENT RULES:

$\displaystyle \mathsf{A^B^+^C=A^B A^C}$

$\displaystyle \mathsf{xx=x^2}}}$

$\displaystyle \mathsf{2xx+2x}}$

2x(x+1)

Factor it out by the -3 from -3x-3.

-3(x+1)

2x(x+1)-3(x+1)

Common term of x+1.

$\Rightarrow \displaystyle \Large\boxed{\mathsf{ \left(x+1\right)\left(2x-3\right)}}}}$

So, the correct answer is (x+1)(2x-3).