Question

2x³-3x²-11x-6 Factorise the equation​

Answer 1

Answer: 2x³ + 3x² - 11x - 6

= 2x³ - 4x² + 7x² - 14x + 3x - 6

= 2x²(x -2) + 7x(x -2) + 3(x -2)

= {2x² + 7x +3}(x -2)

= {2x² + 6x + x + 3}(x -2)

={2x(x +3) + 1(x +3) }(x -2)

= (2x +1)(x +3)(x -2)

hence, zeros of polynomial are , -1/2 , -3 and 2  

Step-by-step explanation:

Answer 2

Answer:

$( x + 1 )( 2xx^{2} - 5x - 6$$)$

Step-by-step explanation:

Factor By Grouping :-

$= 2x^{3} - 3x^{2} - 11x - 6\\= 2x^{3} - 5x^{2} - 6x + 2x^{2} - 5x - 6\\= 2x^{3} - 5x^{2} - 6x + 2x^{2} - 5x - 6\\= x(2x^{2} - 5x - 6) + 2x^{2} - 5x - 6\\= x(2x^{2} - 5x - 6) + 1(2x^{2} - 5x -6)\\\\= ( x + 1 ) ( 2x^{2} - 5x - 6)$

Hope it helps you :).