Question

(2x³ - 7x² – 5x – 4) /(2x - 1)​

Answer 1

Quotient is $x^2-3x-4$ and Remainder is -8.

Step-by-step explanation:

Given;

Dividend = $2x^3-7x^2-5x-4$

Divisor = $2x-1$

We need to find the quotient and remainder.

Solution:

We have attached the division for your reference.

Step 1: Now the Dividend is $2x^3-7x^2-5x-4$ and Divisor is $2x-1$, we will first multiply the divisor with $x^2$ we get $2x^3-x^2$ so $2x^3$ gets cancelled and we get the answer as  $-6x^2-5x-4$ as remainder and Quotient as $x^2$.

Step 2: Now the Dividend is $-6x^2-5x-4$  and Divisor is $2x-1$, we will multiply the divisor with $-3x$ we get $-6x^2+3x$ so $6x^2$ gets cancelled and we get the answer as  $-8x-4$ as remainder and Quotient as $x^2-3x$.

Step 3: Now the Dividend is $-8x-4$ and Divisor is $2x-1$, we will multiply the divisor with $-4$ we get $-8x-4$ so $8x$ gets cancelled and we get the answer as  $-8$ as remainder and Quotient as $x^2-3x-4$.

Now there is no more further division possible.

Hence the Final Answer is

Quotient is $x^2-3x-4$ and Remainder is -8.

Answer 2

Jo upar likha hai vo pura likh lo

is the correct answer