(2x³ + x² + 9x+ 17) ÷ (x - 2)
Find the quotient and the remainder.
Answers
Answered by
1
Answer :
Now,
2x³ + x² + 9x + 17
= 2x³ - 4x² + 5x² - 10x + 19x - 38 + 55
= 2x²(x - 2) +5x(x - 2) + 19(x - 2) + 55
= (x - 2) (2x² + 5x + 19) + 55
∴ the quotient is (2x² + 5x + 19) and the remainder is 55.
#MarkAsBrainliest
Answered by
4
Hi ,
It is given that ,
( 2x³ + x² + 9x + 17 ) ÷ ( x - 2 )
x - 2) 2x³ + x² + 9x + 17 ( 2x²+5x+19
****** 2x³ - 4x²
________________
************ 5x² + 9x
************ 5x² - 10x
________________
****************** 19x + 17
****************** 19x - 38
___________________
*************************( 55 )
Therefore ,
Dividend = 2x³ + x² + 9x + 17
Divisor = x - 2
Quotient = 2x² + 5x + 19
Remainder = 55
I hope this helps you .
: )
It is given that ,
( 2x³ + x² + 9x + 17 ) ÷ ( x - 2 )
x - 2) 2x³ + x² + 9x + 17 ( 2x²+5x+19
****** 2x³ - 4x²
________________
************ 5x² + 9x
************ 5x² - 10x
________________
****************** 19x + 17
****************** 19x - 38
___________________
*************************( 55 )
Therefore ,
Dividend = 2x³ + x² + 9x + 17
Divisor = x - 2
Quotient = 2x² + 5x + 19
Remainder = 55
I hope this helps you .
: )
Similar questions