Question

2xcube +12xsquare +16x

Answer 1

Answer:

${2x}^{3} + {12x}^{2} + 16x = 0 \\ {2x}^{3} + 8 {x}^{2} + 4 {x}^{2} + 16x = 0 \\ 2 {x}^{2} (x + 4) + 4x(x + 4) = 0 \\ (2 {x}^{2} + 4x)(x + 4) = 0 \\ {2x}^{2} + 4 = 0 \: \: \: \: \: \: \: \: \: x + 4 = 0 \\ {2x}^{2} = - 4 \: \: \: \: \: \: \: \: \: \: x = - 4 \\ { {x}^{2} = \frac{ - 4}{2} } \\ \\ x = \sqrt{ - 2}$

Here's ur answer

Step-by-step explanation:

Hope it helps u