2xY + 3 + 2Y + 3x factorize regrouping method
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Answered by
47
2xy + 3x + 2y + 3
= x ( 2y + 3 ) + 1 ( 2y + 3 )
=( X + 1 )( 2y + 3 )
= x ( 2y + 3 ) + 1 ( 2y + 3 )
=( X + 1 )( 2y + 3 )
Answered by
41
2xy + 3 + 2y + 3x
= 3x + 3 + 2y + 2xy
= (3x + 3) + (2xy + 2y)
= 3 (x +1) + 2y ( x + 1)
= (x +1) ( 2y + 3)
= 3x + 3 + 2y + 2xy
= (3x + 3) + (2xy + 2y)
= 3 (x +1) + 2y ( x + 1)
= (x +1) ( 2y + 3)
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