An object height of 8cm placed at a distance of 50cm in front of a convex mirror whose radius of curvature 25cm of mirror and shadow properties is .....
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We know that from mirror equation
1/f = 1/v + 1/u
1/12=1/v+1/61/12=1/v+1/6
1/12−2/12=1/v1/12−2/12=1/v
−1/12=1/v−1/12=1/v
V=−12cm
1/f = 1/v + 1/u
1/12=1/v+1/61/12=1/v+1/6
1/12−2/12=1/v1/12−2/12=1/v
−1/12=1/v−1/12=1/v
V=−12cm
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