Math, asked by abhigyan984, 8 months ago

(-2xy) (-3x3y2) (-1/6x2y7)​

Answers

Answered by mantu9000
3

We have:

(-2xy)(-3x^3y^2)(-\dfrac{1}{6} x^2y^7)

We have to simply to the given expression.

Solution:

(-2xy)(-3x^3y^2)(-\dfrac{1}{6} x^2y^7)

= [(-2)(-3)(-\dfrac{1}{6} )]\times (x \times x^3 \times x^2)\times (y \times y^2 \times y^7)

= [6(-\dfrac{1}{6} )]\times x^{1+3+2} \times y^{1+2+7} [ ∵ a^{m} \times a^{n}  \times a^{o}=a^{m+n+o} ]

= (-1)\times x^{6} \times y^{10}

= -x^{6}y^{10}

(-2xy)(-3x^3y^2)(-\dfrac{1}{6} x^2y^7) = -x^{6}y^{10}

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