Question

(2y – 1) / 3 - (3y + 1) / 4 = y – 6​

Answer 1

Step-by-step explanation:

2y–1/3–3y–1/4=y–6

2y–3y–y=–6+1/3+1/4

–2y=–65/12

y=–65/12/–2

y=1.0833333333

Answer 2

Step-by-step explanation:

Given :-

(2y – 1) / 3 - (3y + 1) / 4 = y – 6

To find:-

Fond the value of y?

Solution:-

Given equation is (2y – 1) / 3 - (3y + 1) / 4 = y – 6

LCM of 3 and 4 = 12

=>[4(2y-1)-3(3y+1)]/12 = y-6

=> (8y-4-9y-3)/12 = y-6

=> (-y-7)/12 = y-6

=> -y-7 = 12(y-6)

=> -y-7 = 12y-72

=> -7+72 = 12y+y

=> 65 = 13y

=> 13y = 65

=> y = 65/13

=> y = 5

Therefore, y = 5

Answer:-

The value of y for the given problem is 5

Check:-

If y = 5 then LHS of the given equation

=> (2y – 1) / 3 - (3y + 1) / 4

=> [2(5)-1]/3 - [3(5)+1]/4

=> (10-1)/3 - (15+1)/4

=> 9/3 - 16/4

=> 3-4

=> -1

LHS = -1

If y = 5 then RHS of the given equation

=> y-6

=> 5-6

=> -1

RHS = -1

Therefore, LHS = RHS is true for y = 5

Verified the given relations in the given problem