Math, asked by muskanmanglani2007, 5 months ago

2y-1/3 - 3y+1/4 =y-6 solve the equation​

Answers

Answered by pawan68319
0

Step-by-step explanation:

(i)

2x

1

+

3y

1

=2;

3x

1

+

2y

1

=

6

13

(ii)

x

2

+

y

3

=2;

x

4

y

9

=−1

(iii)

x

4

+3y=14;

x

3

−4y=23

(iv)

x−1

5

+

y−2

1

=2;

x−1

6

y−2

3

=1

(v)

xy

7x−2y

=5;

xy

8x+7y

=15

(vi) 6x+3y=6xy;2x+4y=5xy

(vii)

x+y

10

+

x−y

2

=4;

x+y

15

x−y

5

=−2

(viii)

3x+y

1

+

3x−y

1

=

4

3

;

2(3x+y)

1

2(3x−y)

1

=

8

−1

pls mark me as brainlist

Answered by Yusifer
2

Answer:

2y - 1/3 - 3y + 1/4= y - 6

2y - y - 3y = 1/3 - 1/4 - 6 (by transposition)

y - 3y = 4/12 - 3/12 - 72/12

- 2y = - 71/12

y = -71/12 ÷ -2

y = - 71/12 × -1/2 ( by reciprocal)

y = 71/24

y = 27/8

Similar questions